Overte identitu cosx 1 + sinx + 1 + sinx cosx = 2secx
sinx,cosx I will work on my sinx and cosx. Thanks for your help. Tim
12 Mar 2015 cosx/1+sinx + 1+sinx/cosx = 2sec. I'd like to know how to solve this problem. We are learning trigonometric identities. Follow 7 Aug 2017 Ill assume its the first one.cos x / ( 1 + sin x) + (1 + sinx ) / cos x= cos^2 x + Verify the identity cosx/1+sinx + 1+sin/cosx = 2sec x.
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sinx,cosx I will work on my sinx and cosx. Thanks for your help. Tim Jun 21, 2010 · (1-sinx) / cosx + cosx / (1-sinx) cross multiply [(1-sinx) ^ 2 + (cosx) ^ 2] / [cosx(1-sinx)] [1 - 2sinx + sinx ^ 2 + cosx ^ 2] / [cosx(1-sinx)] using the identity sinx ^ 2 + cosx ^ 2 = 1 we get [2 - 2sinx] / [cosx(1-sinx)] factor out the 2 [2(1-sinx)] / [cosx(1-sinx)] the (1-sinx) cancle. 2 / cosx. using the identity 1 / cosx = sec x. 2secx.
Example 1: Find the exact value for sin 105° using the half‐angle identity. In the following verification, remember that 105° is in the second quadrant, and sine functions in the second quadrant are positive. Also, 210° is in the third quadrant, and cosine functions in the third quadrant are negative.
0 d. 2+cosx Please show me steps too? :) I tried forever on itand did not get it right Question : cosx/1-sinx=1+sinx/cosx Let's work with the left hand side We're going to times cosx/1-sinx by 1+sinx/1+sinx, you can do this because 1+sinx/1+sinx is equal to 1, so you aren't really changing anything.
You can put this solution on YOUR website! Prove that: Cosx/1-sinx + 1-sinx/cosx = 2secx----- Multiplying left-side by LCD, (1 - sin x)(cos x)----- Substituting 1 for
The first thing you should do is choose the more complex side. In this case, it's the left hand side (LHS). Question : cosx/1-sinx=1+sinx/cosx Let's work with the left hand side We're going to times cosx/1-sinx by 1+sinx/1+sinx, you can do this because 1+sinx/1+sinx is equal to 1, so you aren't really changing anything. Simplify the LHS by first getting a common denominator of sin(x)*(1 + cos(x)).
sinA = 1/cscA. Left hand side =1/tanx(1+cos2x) = 1/(sinx/cosx)(1+cos^2x-sin^2x) = 1/(sinx/cosx(cos^2x+cos^2x)) (tanx+secx-1)(tanx+secx+1) =(tanx+secx)^2 - 1 =tan^2 x + sec^2 x + 2 secx tanx-1 =tan^2 x + sec^2 x - 1 + 2secx tanx =tan^2 x + tan^2 x + 2tanx secx =2tan^2 x + 2 Convert the left side into terms with common denominator and add (converting #cos^2+sin^2# to #1# along the way); simplify and refer to definition of #sec = 1/cos# Ask a question for free Get a free answer to a quick problem. Most questions answered within 4 hours.
5.Prove: cosx 1 sinx 2secx 1 sinx cosx + + = + 6.Prove: 2 cscxcosx cos x tanx cotx = + 7.Prove: 44 22 sin x cos x 1 sin x cos x − = − 8.Prove: 2 2 2. tan x sin x tan x 1 = + 9.Prove: 1 sinx cosx cosx 1 sinx − = + 10.Prove: tan x csc xtan x 1. 2 22=− 11.Prove: cosx secx tanx 1 sinx += − 12.Prove: cscx cotx Nov 30, 2013 · Recall the formula tanA = sinA/cosA. sin2A = 2sinAcosA. cos2A = cos^2A-sin^2A. sinA = 1/cscA.
= 2 cosx. =2secx. Answer link. Most of the work is simple algebra. The identity used was , definition , and Difference of Squares . Answer by MathTherapy (9318) ( Show Source ): You can put this solution on YOUR website!
5.Prove: cosx 1 sinx 2secx 1 sinx cosx + + = + 6.Prove: 2 cscxcosx cos x tanx cotx = + 7.Prove: 44 22 sin x cos x 1 sin x cos x − = − 8.Prove: 2 2 2. tan x sin x tan x 1 = + 9.Prove: 1 sinx cosx cosx 1 sinx − = + 10.Prove: tan x csc xtan x 1. 2 22=− 11.Prove: cosx secx tanx 1 sinx += − 12.Prove: cscx cotx Nov 30, 2013 · Recall the formula tanA = sinA/cosA. sin2A = 2sinAcosA. cos2A = cos^2A-sin^2A.
If the kite is 150 feet above ground and a Q: 12 Suppose that 0 is an Get an answer for 'Observe if sinx + cosx = (cotx + 1)*1/cscx.' and find homework help for other Math questions at eNotes Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Mar 16, 2017 · I can't seem to prove these trig identities and would really appreciate help: 1.
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May 22, 2008 · combine the fractions. cos^2 x + (1-sin x)^2 / [cos x* (1-sin x)]=2sec x. simplify a little. (cos^2 x + 1 - 2sin x + sin^2 x)/ [cos x* (1-sin x)]=2sec x. use Pythagorean trig identity. 2 (1 - sin x)/ [cos x* (1-sin x)]=2sec x. factor out the (1-sin x) 2*1/cos x=2sec x. definition of secant.
Then find and use the common denominator: = cosx*(1+sinx - (1-sinx))/((1-sinx)*(1+sinx)). Take into account that 1-(sinx)^2={cosx)^2 obtain = cosx*2*sinx/(cosx)^2 (cosx/1 + sinx) + (cosx/1-sinx)= (cosx(1-sinx)+cosx(1+sinx))/(1-sin^2x)= (cosx-sinxcosx+cosx+sinxcosx)/cos^2x= 2cosx/cos^2x= 2/cosx= 2secx=2secx What is trigonometryHow to solve trigonometric equationsHow to solve trigonometric identities ChemicalTech Academy provides free tutorial videos in areas suc Trigonometry Formula List: https://www.youtube.com/watch?v=EaSV-VasbnQ&list=PLJ-ma5dJyAqqEv5UpYmUFj6PVyMpHrLZ6&index=1 Step-by-step Solution Prove the trigonometric identity $\frac{1+\sin\left(x\right)}{\cos\left(x\right)}+\frac{\cos\left(x\right)}{1+\sin\left(x\right)}=2\sec\left(x Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.1.